giles c8206e718a ocaml: phase 5.1 max_product3.ml baseline (max product of 3, with negatives -> 300) ...

Sort, then compare two candidates:
  p1 = product of three largest values
  p2 = product of two smallest (potentially negative) values and the largest

For [-10;-10;1;3;2]:
  sorted    = [-10;-10;1;2;3]
  p1        = 3 * 2 * 1                = 6
  p2        = (-10) * (-10) * 3        = 300
  max       = 300

Tests List.sort + Array.of_list + arr.(n-i) end-walk + candidate-pick
via if-then-else.

104 baseline programs total.

2026-05-09 20:46:42 +00:00

2.3 KiB

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