giles 67a5f13713 HS: in-expression filter semantics (+1 test) ...

`1 in [1, 2, 3]` must return (list 1) not true. Root cause: in? compiled
to hs-contains? which returns boolean for scalar items. Fix: new hs-in?
returns filtered list; new in-bool? operator for is/am-in comparison
contexts so those still return boolean. Parser generates in-bool? for
`X is in Y` / `X am in Y`; plain `in` keeps in? → list return.

Co-Authored-By: Claude Sonnet 4.6 <noreply@anthropic.com>

2026-04-25 18:35:26 +00:00

90 KiB

Raw Blame History

View Raw