ocaml: phase 5.1 egg_drop.ml baseline (2 eggs, 36 floors -> 8 trials)
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Classic egg-drop puzzle DP:

  dp[e][f] = 1 + min over k in [1, f] of
              max(dp[e-1][k-1], dp[e][f-k])

For 2 eggs over 36 floors, the optimal worst-case is 8 trials
(closed form: triangular number bound).

Tests 2D DP with triple-nested for-loops, max-of-two via inline
if, large sentinel constant (100000000), mixed shifted indexing
(e-1) and (f-k) where both shift independently.

163 baseline programs total.
This commit is contained in:
2026-05-10 22:58:13 +00:00
parent 62712accdd
commit 32f6c4ee0c
3 changed files with 35 additions and 0 deletions

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@@ -0,0 +1,26 @@
let egg_drop eggs floors =
let dp = Array.init (eggs + 1) (fun _ -> Array.make (floors + 1) 0) in
for f = 1 to floors do
dp.(1).(f) <- f
done;
for e = 1 to eggs do
dp.(e).(0) <- 0;
dp.(e).(1) <- 1
done;
for e = 2 to eggs do
for f = 2 to floors do
let best = ref 100000000 in
for k = 1 to f do
let bre = dp.(e - 1).(k - 1) in
let sur = dp.(e).(f - k) in
let cand = 1 + (if bre > sur then bre else sur) in
if cand < !best then best := cand
done;
dp.(e).(f) <- !best
done
done;
dp.(eggs).(floors)
;;
egg_drop 2 36

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@@ -29,6 +29,7 @@
"count_change.ml": 406,
"count_inversions.ml": 12,
"csv.ml": 10,
"egg_drop.ml": 8,
"dijkstra.ml": 7,
"exception_handle.ml": 4,
"exception_user.ml": 26,

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@@ -407,6 +407,14 @@ _Newest first._
binary search tree (`type 'a tree = Leaf | Node of 'a * 'a tree *
'a tree`) with insert + in-order traversal. Tests parametric ADT,
recursive match, List.append, List.fold_left.
- 2026-05-10 Phase 5.1 — egg_drop.ml baseline (worst-case trials
for 2 eggs, 36 floors = 8). Classic O(e·f²) DP: dp[e][f] = 1 +
min over k of max(dp[e-1][k-1], dp[e][f-k]). Closed form via
triangular numbers gives ⌈(√(1+8·36)1)/2⌉ = 8, matching the
DP answer. Tests 2D DP with triple-nested for-loops, max-of-two
via inline if, large sentinel constant, mixed indexing (e-1)
and (f-k) where both shift independently. 163 baseline programs
total.
- 2026-05-10 Phase 5.1 — polygon_area.ml baseline (shoelace formula
on pentagon, returns 2× area = 32). Vertices (0,0), (4,0), (4,3),
(2,5), (0,3); shoelace sum |Σ(x_i·y_{i+1} x_{i+1}·y_i)| = 32 so