giles
f1df5b1b72
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Uses the identities:
F(2k) = F(k) * (2 * F(k+1) - F(k))
F(2k+1) = F(k)^2 + F(k+1)^2
to compute Fibonacci in O(log n) recursive depth instead of O(n).
let rec fib_pair n =
if n = 0 then (0, 1)
else
let (a, b) = fib_pair (n / 2) in
let c = a * (2 * b - a) in
let d = a * a + b * b in
if n mod 2 = 0 then (c, d)
else (d, c + d)
Each call returns the pair (F(n), F(n+1)). fib(40) = 102334155 fits
in JS safe-int (< 2^53). Tests tuple returns with let-tuple
destructuring + recursion on n / 2.
86 baseline programs total.