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Find the unique Pythagorean triple with a + b + c = 1000 and
return their product.
The naive triple loop timed out under host contention (10-minute
cap exceeded with ~333 * 999 ~= 333k inner iterations of complex
checks). Rewritten with algebraic reduction:
a + b + c = 1000 AND a^2 + b^2 = c^2
=> b = (500000 - 1000 * a) / (1000 - a)
so only the outer a-loop is needed (333 iterations). Single-pass
form:
for a = 1 to 333 do
let num = 500000 - 1000 * a in
let den = 1000 - a in
if num mod den = 0 then begin
let b = num / den in
if b > a then
let c = 1000 - a - b in
if c > b then result := a * b * c
end
done
Triple (200, 375, 425), product 31875000.
103 baseline programs total.