flow: timeout combinator — cooperative step budget + 7 tests (Phase 2 complete)
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(timeout budget node) bounds a node deterministically: nodes opt in via (tick),
budget ticks are allowed, the next raises flow-timeout. No scheduler/clock in pure
SX so the budget is a step count, not wall-clock. Budgets nest and are per-run.

Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
This commit is contained in:
2026-06-06 16:42:16 +00:00
parent 4674620d7e
commit e762cc2e32
5 changed files with 58 additions and 11 deletions

View File

@@ -140,4 +140,40 @@
"(define ctr 0) (flow/start (sequence (retry 5 (lambda (x) (set! ctr (+ ctr 1)) (fail (quote bad)))) (lambda (f) ctr)) 0)")
1)
;; ── timeout — cooperative step budget ───────────────────────────
(flow-ctl-test
"timeout: work within budget completes"
(flow-c
"(define (cd n) (if (<= n 0) 99 (begin (tick) (cd (- n 1))))) (flow/start (try-catch (timeout 10 (lambda (x) (cd x))) (flow-const (quote timed-out))) 5)")
99)
(flow-ctl-test
"timeout: work exceeding budget raises flow-timeout"
(flow-c
"(define (cd n) (if (<= n 0) 99 (begin (tick) (cd (- n 1))))) (flow/start (try-catch (timeout 10 (lambda (x) (cd x))) (flow-const (quote timed-out))) 20)")
"timed-out")
(flow-ctl-test
"timeout: exact budget boundary completes"
(flow-c
"(define (cd n) (if (<= n 0) 99 (begin (tick) (cd (- n 1))))) (flow/start (try-catch (timeout 5 (lambda (x) (cd x))) (flow-const (quote timed-out))) 5)")
99)
(flow-ctl-test
"timeout: one tick over the budget raises"
(flow-c
"(define (cd n) (if (<= n 0) 99 (begin (tick) (cd (- n 1))))) (flow/start (try-catch (timeout 5 (lambda (x) (cd x))) (flow-const (quote timed-out))) 6)")
"timed-out")
(flow-ctl-test
"timeout: the raised error is identifiable"
(flow-c
"(define (cd n) (if (<= n 0) 99 (begin (tick) (cd (- n 1))))) (flow/start (try-catch (timeout 2 (lambda (x) (cd x))) (lambda (e) e)) 9)")
"flow-timeout")
(flow-ctl-test
"timeout: a node that never ticks is unbounded"
(flow-c "(flow/start (timeout 0 (lambda (x) (* x 2))) 5)")
10)
(flow-ctl-test
"timeout: budget is restored across sequential timeouts"
(flow-c
"(define (cd n) (if (<= n 0) 1 (begin (tick) (cd (- n 1))))) (flow/start (sequence (timeout 4 (lambda (x) (cd x))) (timeout 4 (lambda (x) (cd 3))) (lambda (x) (begin (tick) (+ x 100)))) 3)")
101)
(define flow-ctl-tests-run! (fn () {:total (+ flow-ctl-pass flow-ctl-fail) :passed flow-ctl-pass :failed flow-ctl-fail :fails flow-ctl-fails}))