datalog: dl-walk handles circular substitutions without infinite loop (257/257)
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Bug: dl-walk would infinite-loop on a circular substitution
(e.g. A→B and B→A simultaneously). The walk endlessly chased
the cycle. This couldn't be produced through dl-unify (which has
cycle-safe behavior via existing bindings), but raw dl-bind calls
or external manipulation of the subst dict could create it.

Fix: dl-walk now threads a visited-names list through the
recursion. If a variable name is already in the list, the walk
stops and returns the current term unchanged. Normal chained
walks are unaffected (A→B→C→42 still resolves to 42).

1 new unify test verifies circular substitutions don't hang.
This commit is contained in:
2026-05-11 07:20:20 +00:00
parent a9e4eea334
commit 9a16f27075
4 changed files with 32 additions and 11 deletions

View File

@@ -33,16 +33,28 @@
;; variable. The result is either a non-variable term or an unbound var.
(define
dl-walk
(fn (term subst) (dl-walk-aux term subst (list))))
;; Internal: walk with a visited-var set so circular substitutions
;; (from raw dl-bind misuse) don't infinite-loop. Cycles return the
;; current term unchanged.
(define
dl-walk-aux
(fn
(term subst)
(term subst visited)
(if
(dl-var? term)
(let
((name (symbol->string term)))
(if
(and (dict? subst) (has-key? subst name))
(dl-walk (get subst name) subst)
term))
(cond
((dl-member? name visited) term)
((and (dict? subst) (has-key? subst name))
(let ((seen (list)))
(do
(for-each (fn (v) (append! seen v)) visited)
(append! seen name)
(dl-walk-aux (get subst name) subst seen))))
(else term)))
term)))
;; Bind a variable symbol to a value in subst, returning a new subst.