Fix repeat timing: don't double-drive IO suspensions

The value_to_js resume handler was calling _driveAsync on re-suspension,
but the JS driveAsync caller also processes the returned suspension.
This caused the second wait in each iteration to fire immediately (0ms)
instead of respecting the delay.

Fix: resume handler just returns the suspension object, lets the JS
driveAsync handle scheduling via setTimeout.

Verified: repeat 3 times add/wait 300ms/remove/wait 300ms produces
6 transitions at correct 300ms intervals (1504ms total).

Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>
This commit is contained in:
2026-04-09 21:47:48 +00:00
parent 9982cd5926
commit 0bed9e3664
3 changed files with 8 additions and 16 deletions

View File

@@ -121,11 +121,8 @@ let rec value_to_js (v : value) : Js.Unsafe.any =
try value_to_js (Sx_vm.resume_vm v result)
with
| Sx_vm.VmSuspended (req2, vm2) ->
let s = make_suspension req2 vm2 in
let drive = Js.Unsafe.get Js.Unsafe.global (Js.string "_driveAsync") in
if not (Js.Unsafe.equals drive Js.undefined) then
ignore (Js.Unsafe.fun_call drive [| Js.Unsafe.inject s |]);
Js.Unsafe.inject s
(* Return suspension object — the JS driveAsync caller handles scheduling *)
Js.Unsafe.inject (make_suspension req2 vm2)
| Eval_error msg ->
ignore (Js.Unsafe.meth_call
(Js.Unsafe.get Js.Unsafe.global (Js.string "console"))